Solution: det (A) = −5, and for n×n matrix adj (A) has determinant (det A)^ (n−1). Here n = 3, so det (B) = (−5)^ (2) = 25. For feedback or story ideas, reach us at [email protected] ...

Candidates preparing for JEE Advanced 2026 can download the official syllabus PDF from jeeadv.ac.in, released by IIT Roorkee.

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Joint Entrance Exam (JEE) Advanced 2015 will be conducted on May 24, 2015. To appear for the exam, candidates are required to clear the JEE Main Exam 2015 to qualify for the JEE Advanced Exam 2015.

In the year 2024, nearly 12 lakh students have enlisted for the JEE Main examination, with a predominant focus on BE/B. Tech. The examination encompasses the subjects of Physics, Chemistry, and ...

The JEE Advanced 2026 syllabus PDF is now available on the official website, jeeadv.ac.in. The detailed syllabus provides ...