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  1. appdate中的ACLOS可以删除吗? - 知乎

    appdate中的ACLOS可以删除吗(本人不在意游戏文件,和数据)? [图片] 显示全部

  2. AC power supply N and L - All About Circuits

    Jan 4, 2015 · In AC power supply, there are two symbols L and N. N is Neutral while L is Live or Line? N is Neutral: Does it mean this wire is connected to ground and so it always 0V compared to ground. L …

  3. EWC 电竞世界杯与 ACL 亚洲冠军联赛之间的关系是什么? - 知乎

    尽管ACL在LOL项目板块没有队伍选拔的权限,但ACL依然不希望LOL板块的流量直接缺失,他和虎牙的传奇杯二者一拍即合,虎牙有成熟的老头杯办赛经验与人员组织包括外宣渠道,ACL有钱有资质,老 …

  4. r'e Transistor Internal ac Emitter Resistance - All About Circuits

    Aug 1, 2022 · Acl=- gmRc/ (1+gmRE)=Rc/ [ (1/gm)+RE]=Rc/ [rè + RE]. Therefore, when RE>>rè, the small differential part rè can be neglected. Hence, such a simplification may be allowed only when …

  5. NLP领域国际顶会(ACL/EMNLP/NAACLl等)的难度如何? - 知乎

    ACL、EMNLP、NAACL(北美分会)、COLING是NLP领域的四大顶会。前三个会由ACL(Association of Computational Linguistics)主办,COLING由ICCL(International Committee on Computational …

  6. Op-amp biasing not working as intended | All About Circuits

    Nov 17, 2025 · How did you find the resistor values in the negative feedback path (determining the closed-loop gain Acl) ? Note that classic Sallen-Key filters are designed for maximum non-inverting …

  7. 如何看待ACL 2023的录用结果? - 知乎

    在ACL的投稿过程中,我们出于文章整体考虑,弱化了这些特性的介绍,对此审稿人提出疑问,需要我们详细解释,因此在ACL最后的版本中,我们将相应详细的介绍放在了3.1部分对应的附录内容中。

  8. Confusion closed-loop gain equation inverting amplifier

    Apr 10, 2024 · (These expressions result from superposition of both, input and feedback signal, at the inverting input.) As the result - the closed-loop transfer function is Acl=Hf * Ao / (1+Hr * Ao) As you …

  9. NLP 的会议中 workshop,findings 和 short paper 是什么? - 知乎

    ACL系列的NLP会议(如ACL,NAACL和EMNLP)的论文接收大概分几种情况: 1. long paper:分两种。 oral,需要作者上台讲一讲; poster 海报论文,作者制作一张海报与参会者交流,很难区分oral …

  10. Non-Ideal op amp gain. - All About Circuits

    Jan 3, 2014 · I am really lost on this. The question asks to find the op amp voltage gain of the non ideal op amp pictured below. It give open loop conditions: Rin = 400kΩ Rout = 2kΩ Gain = 500k Actually …